Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A cannonball is fired in the air at an Angel of 45 degree. How far does it travel before it is 900 feet above ground.

Sagot :

Answer:

900√2 or 1272.79 ft.

Step-by-step explanation:

Imagine this cannonball making a triangle. When it reaches 900 feet, it will make a straight line down to the ground, making a leg. The imaginary line and ground make up the legs of the triangle with a 90° angle.

We can use the 45-45-90 triangle method

This means the hypotenuse is √2 times the length of a leg

900 x √2 = 1272.79221

View image Polyblock
View image Polyblock