Answer:
The speed of bacterium in kilometers per hour is [tex]7.02\times10^{-3}\rm{km/hour}[/tex].
Explanation:
Given:
The distance covered by the bacterium is [tex]d=6.82\rm{micron}[/tex]
The time taken by the bacterium is [tex]t=3.5[/tex] s.
Now, conversion of units can be done as,
[tex]1\rm{micron}=1\rm{\[\mu\]m}\\1\rm{micron}=1\times10^{-6}\rm{m}[/tex]
[tex]1\rm{m}=1\times10^{-3}\rm{km}[/tex]
[tex]1\rm{s}=\frac{1}{3600}\rm{hour}[/tex]
Now, the speed of bacterium will be,
[tex]s=\frac{d}{t}\\s=\frac{6.83}{3.5}\mu\rm{m/s}[/tex]
Convert the units to km/hour as,
[tex]s=\frac{6.83}{3.5}\mu\rm{m/s}\\s=\frac{6.83}{3.5}\times\frac{10^{-6}}{\frac{1}{3600}}\rm{km/hour}\\s=0.007025\rm{km/hour}\\s=7.02\times10^{-3}\rm{km/hour}[/tex]
Therefore, the speed of bacterium in km per hour is [tex]7.02\times10^{-3}\rm{km/hour}[/tex].
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