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Find three consecutive odd numbers such that the sum of five times the smaller number and twic the larger number is 33 more than six times the median number

Sagot :

ferrybukantoro

Answer:

37, 39, and 41

Step-by-step explanation:

let the numbers are A, (A+2), (A+4)

the equation could be :

5A + 2(A+4) = 33 + 6(A+2)

5A+2A+8 = 33 + 6A+12

7A+8 = 45+6A

7A-6A = 45-8

A = 37

so, the three odd numbers are :

37, 39, and 41

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