ccutler4p6kzkm
Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Jason is pulling a box across the room. He is pulling with a force of 14 newtons and his arm is making a 48 angle with the horizontal, what is the vertical component of the force he is pulling with?

Sagot :

whitneytr12

When Jason pulls a box with a force of 14 N, making a 48 angle between his arms and the horizontal, the vertical component of the force he is pulling is 10.40 N.

We can calculate the vertical component imaging a right triangle with the following dimensions:

H: is the hypotenuse = applied force (F) = 14 N (in the direction of Jason's arms)

A: is the adjacent side = horizontal component of the force

O: is the opposite side = vertical component of the force =?  

θ: is the angle with the horizontal = 48°

Hence, we can find the vertical component with the following trigonometric function:

[tex] sin(\theta) = \frac{O}{H} [/tex]

[tex] O = sin(\theta)*H = sin(48)*14 N = 10.40 N [/tex]

Therefore, the vertical component of the force he is pulling is 10.40 N.

You can see more about force here: https://brainly.com/question/14131556?referrer=searchResults

I hope it helps you!  

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.