The surface area of an object is the total area covered by the object's surface
The inequality that gives the maximum dimension of a cubic block covered twice with a quantity of paint that will cover 60 in.² is b ≤ √5
Question: The diagram in the question appear missing and an example diagram is included
The given parameters are;
The quantity of paint available = Cans of paint that will cover 60 in.²
The number of coats of paint to apply to the box = 2
Required:
To write an inequality representing the maximum edge length, b, in inches when the block is covered with a minimum amount of paint needed for two coats of paint
Solution:
From the diagram, we have;
The surface area of the cube = 6 × b²
The surface area covered by two coats of paint = 2 × 6 × b²
Therefore, we have;
The area of the block to cover ≤ The quantity of paint available
Which gives
2 × 6 × b² ≤ 60
b² ≤ 60/(2 × 6) = 5
b ≤ √5
The inequality that gives the maximum length of b that can be covered with the minimum amount of paint needed for two coats of paint is b ≤ 5
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