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Sagot :
Answer:
solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).
Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒40=20+30−n(A∩B)
⇒40=50−n(A∩B)
⇒n(A∩B)=50−40
⇒n(A∩B)=10
Hence, n(A∩B)=10
Step-by-step explanation:
hope it helps you friend ☺️
n(a) =40
n(b) =30
n(aπb) =20
n(aub)=x (let)
we know that
n(aub)=n(a)+n(b)–n(aπb)
x=40+30–20
x=70-20
x=50
n(aub)=50
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