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Sagot :
Answer:
how high will the ceiling be at the center? ≈43.3 ft above the center
Step-by-step explanation:
standard form of equation for an ellipse with horizontal major axis and center at the origin:
x^2/a^2+y^2/b^2=1, a>b
for given problem:
a=50
a^2=2500
c=25
c^2=625
c^2=a^2-b^2
b^2=a^2-c^2=2500-625=1875
b=√1875≈43.3 ft
≈43.3 ft above the center
Height of celling from center is 43.3 feet (Approx.)
Given that;
Length of hall = 100 feet
Foci length from center = 25 feet
Find:
Height of celling from center
Computation:
Half length of hall = 100 / 2 = 50 feet
Height of celling from center = √Half Length of hall² - Foci length from center²
Height of celling from center = √50² - 25²
Height of celling from center = √2500 - 625
Height of celling from center = √1875
Height of celling from center = 43.3 feet (Approx.)
Learn more:
https://brainly.com/question/10726356?referrer=searchResults
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