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4y = 38 -1/2 (4y + 16)

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\large \mathfrak{Solution : }[/tex]

let's solve for y :

  • [tex]4y = 38 - \dfrac{1}{2} (4y + 16)[/tex]

  • [tex]4y = 38 - 2y - 8[/tex]

  • [tex]4y + 2y = 30[/tex]

  • [tex]6y = 30[/tex]

  • [tex]y = 30 \div 6[/tex]

  • [tex]y = 5[/tex]

value of y = 5

Answer:

[tex]y=5[/tex]

Step-by-step explanation:

[tex]4y=38-\frac{1}{2}\left(4y+16\right)[/tex]

→ Multiply fractions:- [tex]a\times\frac{b}{c} =\frac{a\times b}{c}[/tex]

[tex]\frac{1\cdot \left(4y+16\right)}{2}[/tex]

[tex](4y+16)=4y+16[/tex]

[tex]4y=38-\frac{4y+16}{2}[/tex]

→ Multiply both sides by 2:-

[tex]y\cdot \:2=38\cdot \:2-\frac{4y+16}{2}\cdot \:2[/tex]

[tex]8y=76-\left(4y+16\right)[/tex]

[tex]76-(4y+16)=-4x+60[/tex]

[tex]8y=-4y+60[/tex]

→ Add 4y to both sides:-

[tex]8y+4y=-4y+60+4y[/tex]

[tex]12y=60[/tex]

→ Now, divide both sides by 12:-

[tex]\frac{12y}{12}=\frac{60}{12}[/tex]

[tex]y=5[/tex]

OAmalOHopeO

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