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What is the acceleration of a runner who increases her velocity from 2m/s to 8m/s in 3s?

Sagot :

  • initial velocity=u=2m/s
  • Final velocity=v=8m/s
  • Time=t=3s

[tex]\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{8-2}{3}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{6}{3}[/tex]

[tex]\\ \sf\longmapsto Acceleration=2m/s^2[/tex]

Answer: 2 m/s^2

Explanation:

V1-Vf/ T

2m/s - 8m/s / 3s

6m/s / 3s =

2 m/s^2