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A restaurant owner can buy ketchup bottles in boxes of 10 and mustard bottles in boxes of 6. The owner bought the fewest number of ketchup and mustard bottles so that there is exactly one ketchup bottle per mustard bottle with none left over. How many boxes of ketchup bottles and how many boxes of mustard bottles did the restaurant owner buy?

Sagot :

latifahmbabazi483

Answer:

0•6

Step-by-step explanation:

d=10-6

d=4

=1÷4×6

=3/2

Using the least common multiple, it is found that the owner bought 3 boxes of ketchup and 5 boxes of mustard.

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  • Ketchup bottles are sold in boxes of 10.
  • Mustard bottles are sold in boxes of 6.
  • The smallest number of each ketchup and mustard that can be bought is given the least common multiple of 6 and 10, thus, factoring both numbers:

6 - 10|2

3 - 5|3

1 - 5|5

1 - 1

Thus, lcm(6,10) = 2x3x5 = 30

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  • The owner bought 30 ketchups and 30 mustards.
  • 30/10 = 3 ketchup boxes.
  • 30/6 = 5 mustard boxes.

A similar problem is given at https://brainly.com/question/21329937

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