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Sagot :
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
Happy to help :)
If u need any help feel free to ask
Answer:
6.) QS = 16
7.) QS = 8
Step-by-step explanation:
The midpoint splits the segment into 2 equal segments. Therefore, set both expressions equal to each other and solve for x.
6.)
[tex]QR=RS\\\\x+6=4x\\\\x+6-x=4x-x\\\\6=3x\\\\\frac{6}{3}=\frac{3x}{3}\\\\2=x\\\\\\QR+RS=QS\\\\(2)+6+4(2)=QS\\\\16=QS[/tex]
7.)
[tex]QR=RS\\\\3x-2=2x\\\\3x-2-3x=2x-3x\\\\-2=-x\\\\\frac{-2}{-1}=\frac{-x}{-1}\\\\2=x\\\\\\QR+RS=QS\\\\3(2)-2+2(2)=QS\\\\8=QS[/tex]
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