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Answered

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The width of a certain rectangle is 5 inches less than the length. Find the dimensions of the rectangle if its perimeter is 42 in.

Sagot :

Leora03

Answer:

13 in. ×8 in.

Step-by-step explanation:

Perimeter of rectangle= 2(length +width)

Let the length be L in. and the width be W in.

Given: perimeter= 42 in.,

W= L -5 -----(1)

42= 2(L +W)

Divide both sides by 2:

21= L +W -----(2)

Substitute (1) into (2):

21= L +L -5

21= 2L -5

2L= 21 +5

2L= 26

L= 26 ÷2

L= 13

Substitute L= 13 into (1):

W= 13 -5

W= 8

Width= 8 in.

Length= 13 in.

Therefore, the dimensions of the rectangle is 13 in. ×8 in.

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