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point A is at (6,-6) and point C is at (-6,2) . Find the coordinate of point B on AC such that AB=3/4 AC​

Sagot :

Step-by-step explanation:

[tex]\begin{tabular}{c | l}

Atomic Number & Element \\

\cline{1-2}

1 & Hydrogen \\

2 & Helium \\

3 & Lithium \\

4 & Beryllium \\

5 & Boron \\

6 & Carbon

\end{tabular}[/tex]

[tex]\begin{tabular}{c | l}

Atomic Number & Element \\

\cline{1-2}

1 & Hydrogen \\

2 & Helium \\

3 & Lithium \\

4 & Beryllium \\

5 & Boron \\

6 & Carbon

\end{tabular}[/tex]

[tex]\begin{tabular}{|c|c|c|c|}

\cline{1-4}

\multicolumn{4}{|c|}{Elementary Particles} \\

\cline{1-4}

\multicolumn{2}{|c|}{Fermions} &

\multicolumn{2}{c|}{Bosons} \\

\cline{1-4} Quarks & Leptons & Gauge Bosons & Scalar Bosons \\

\cline{1-4} Up & Electron & Photon & Higgs Boson \\

Down & Electron Neutrino & W and Z Bosons & \\

Charm & Muon & Gluons & \\

Strange & Muon Neutrino & & \\

Top & Tau & & \\

Bottom & Tau Neutrino & & \\

\cline{1-4}

\end{tabular}[/tex]

[tex]\boxed{

\begin{minipage}{7 cm}

Fundamental Trigonometric Identities \\ \\

$\sin^2\theta + \cos^2\theta=1 \\ \\

1+\tan^2\theta = \sec^2\theta \\ \\

1+\cot^2\theta = \text{cosec}^2 \, \theta$

\end{minipage}[/tex]