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Sagot :
WE have that the flow velocity is
[tex]v=333.3 mts/h[/tex]
Distance traveled = 691 m
time = 38.1 min
speed(boat) =[tex]\frac{ 691}{38.1} =18.14 m/min[/tex]
Distance traveled = 691 m
Generally the equation for down stream speed is mathematically given as
[tex]t= 691/(18.14-v)[/tex]
Where
down stream speed = (18.14+v)
[tex]d = 2*691 m[/tex]
Therefor
[tex]t=\frac {2*691}{(18.14+v)}[/tex]
Generally the total time to reach starting point is
[tex]T= \frac{2*691}{(18.14+v)}+ \frac{691}{(18.14-v)}[/tex]
To find the speed of the log v is
d= 691 m
t= 691/v
[tex]\frac{691}{v }= \frac{2*691}{(18.14+v)}+ \frac{691}{(18.14-v)}\\\\\691(18.14^2-v^2)=691v(18.14+v)+1382v(18.14-v)\\\\227380-691v^2=12534.74V+691v^2+25069.48V-1382v^2[/tex]
Therefore
[tex]V=2.756*10^{-3} m/s\\\\v= \frac{10^9}{3} *10^6[/tex]
[tex]v=333.3 mts/h[/tex]
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