karsonmelt91006
Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The tallest building in Franklin is two-thirds the
height of the tallest building in Mayville. If the
tallest building in Mayville is 80 13/16 feet, find
the height of the tallest building in Franklin.

Sagot :

aksnkj

Answer:

The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.

Step-by-step explanation:

Given:

The height of tallest building in Mayville is [tex]80\[\frac{13}{16}\][/tex] feet or [tex]\[\frac{1293}{16}\][/tex] feet. (Simplifying the fraction)

And the tallest building in Franklin is 2/3rd of the tallest building in Mayville.

So, multiply the height of Mayville with [tex]\[\frac{2}{3}\][/tex] to get the height of tallest building in Franklin.

Thus, the height of tallest building in Franklin will be,

[tex]h=\[\frac{1293}{16}\]\times\frac{2}{3}\\h=\frac{431}{8}\\h=53\frac{7}{8}[/tex]

The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.

For more details, refer to the link:

https://brainly.com/question/6201432?referrer=searchResults

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.