karsonmelt91006
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The tallest building in Franklin is two-thirds the
height of the tallest building in Mayville. If the
tallest building in Mayville is 80 13/16 feet, find
the height of the tallest building in Franklin.

Sagot :

aksnkj

Answer:

The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.

Step-by-step explanation:

Given:

The height of tallest building in Mayville is [tex]80\[\frac{13}{16}\][/tex] feet or [tex]\[\frac{1293}{16}\][/tex] feet. (Simplifying the fraction)

And the tallest building in Franklin is 2/3rd of the tallest building in Mayville.

So, multiply the height of Mayville with [tex]\[\frac{2}{3}\][/tex] to get the height of tallest building in Franklin.

Thus, the height of tallest building in Franklin will be,

[tex]h=\[\frac{1293}{16}\]\times\frac{2}{3}\\h=\frac{431}{8}\\h=53\frac{7}{8}[/tex]

The height of tallest building in Franklin is [tex]\[\frac{431}{8}\][/tex] feet or [tex]53\[\frac{7}{8}\][/tex] feet.

For more details, refer to the link:

https://brainly.com/question/6201432?referrer=searchResults

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