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Question 2(Multiple Choice Worth 1 points)
(01.02 LC)

Solve for x: the quantity of (x plus 20) over 2 = 3x

x = 10
x = 4
x = −14
x = −17


Sagot :

X=4
(X+20)/2 = 3x
Multiply everything by 2 to cancel out the 2; therefore, (x+20)= 6x
Now solve for x,
20= 6x-x
20= 5x
Divide everything by 5 to solve for x,
20\5 = 5x/5
4=x
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