Answered

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Write the equation of the line that passes through (3,6) and is parallel to y = 2/3x+2.

Sagot :

Theekshana

Answer:

[tex]y=\frac{2}{5}x-5[/tex]

Step-by-step explanation:

[tex]y=\frac{2}{3}x+4[/tex]

the line parallel  to this line is

[tex]y=\frac{2}{3}x+k[/tex] ; k ∈ R

the line passes through the point (3,6)

so,

[tex]6=\frac{2}{3} (3)+k\\6=2 +k\\k=4[/tex]

∴the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6 is

[tex]y=\frac{2}{3}x+4[/tex]

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