Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Write the equation of the line that passes
through (4,-5) and is parallel to y=-2x-4.

Sagot :

amysun2025

Answer:

y=-2x+3

Step-by-step explanation:

Hi there!

We are given the point (4, -5) and we want to write the equation of the line that passes through that point and is parallel to the line y= -2x-4

Parallel lines have the same slope, but different y intercepts.

So let's find the slope of the line y=-2x-4

The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

As -2 is in the place of where m, the slope is, then -2 is the slope of the line. It is also the slope of the line parallel to it.

So let's write the equation of this new line in slope-intercept form. So far, we have:

y=-2x+b

So we need to find b

As the equation passes through the point (4, -5), we can substitute its values into the equation to solve for b

So substitute 4 as x and -5 as y in y=-2x+b

-5=-2(4)+b

Multiply

-5=-8+b

Add 8 to both sides

3=b

Substitute 3 as b in the equation

y=-2x+3

Hope this helps!

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.