Answered

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Write the equation of the line that passes through
(6,-5) and is perpendicular to y = 2x+3.

Sagot :

devishri1977

Answer:

Step-by-step explanation:

y = 2x + 3

Slope = 2

The slope of the perpendicular line = -1/m = -1/2

m = -1/2 ; (6, -5)

y = mx +b

Here, plugin x = 6 ; y = -5  and m = -1/2

[tex]-5 = \dfrac{-1}{2}*6+b\\\\-5=-3+b\\\\\\-5 + 3 = b\\\\b = -2[/tex]

Equation of the line: y = mx +b

[tex]y =\dfrac{-1}{2}x -2[/tex]

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