Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Write the equation of the line that passes through
(6,-5) and is perpendicular to y = 2x+3.

Sagot :

devishri1977

Answer:

Step-by-step explanation:

y = 2x + 3

Slope = 2

The slope of the perpendicular line = -1/m = -1/2

m = -1/2 ; (6, -5)

y = mx +b

Here, plugin x = 6 ; y = -5  and m = -1/2

[tex]-5 = \dfrac{-1}{2}*6+b\\\\-5=-3+b\\\\\\-5 + 3 = b\\\\b = -2[/tex]

Equation of the line: y = mx +b

[tex]y =\dfrac{-1}{2}x -2[/tex]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.