Answered

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Write the equation of the line that passes through
(6,-7) and is perpendicular to y = 2/3x+1.

Sagot :

devishri1977

Answer:

Step-by-step explanation:

y = (2/3)x + 1

m = 2/3

The slope of the perpendicular line = -1/m

                                         [tex]Slope = \dfrac{-1}{\dfrac{2}{3}}=-1*\dfrac{3}{2}=\dfrac{-3}{2}\\\\\\(6,-7) ; \ x_{1}= 6 \ ; y_{1} = -7\\\\\\Equation: y-y_{1}=m(x-x_{1})\\\\\\y -[-7] = \dfrac{-3}{2}(x - 6)\\\\\\y + 7 = \dfrac{-3}{2}x - 6*\dfrac{-3}{2}\\\\y +7=\dfrac{-3}{2}x+9\\\\y = \dfrac{-3}{2}x+9-7\\\\y =\dfrac{-3}{2}x+2[/tex]

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