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Given that f(x)=x^(2)-14 and g(x)=9-x, find (f-g)(6), if it exists.

Sagot :

mhanifa

Answer:

  • -5

Step-by-step explanation:

Given:

  • f(x) = x² - 14 and g(x) = 9 - x

Find (f-g)(6):

  • g(6) = 9 - 6 = 3
  • (f-g)(6) = f(g(6)) = f(3) = 3² - 14 = 9 - 14 = -5

f(x)=x^2-14

g(x)=9-x

Find g(6)

[tex]\\ \sf\longmapsto g(6)=9-6=3[/tex]

Now

[tex]\\ \sf\longmapsto (f-g)(x)=f(g(x))[/tex]

[tex]\\ \sf\longmapsto f(g(6))[/tex]

[tex]\\ \sf\longmapsto f(3)[/tex]

[tex]\\ \sf\longmapsto 3^2-14[/tex]

[tex]\\ \sf\longmapsto 9-14[/tex]

[tex]\\ \sf\longmapsto -5[/tex]

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