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Find four consecutive integers whose sum is 17802.

Sagot :

The four numbers will each be about ¼ of 17802, which is 4450.5. Take two numbers on each side of 4450.5 and we have 4449, 4450, 4451, and 4452, which sum to 17802.

Or write an equation: x + (x + 1) + (x + 2) + (x + 3) = 17802.
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