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Sagot :
Probabilities are used to determine the possibility of an event.
The probability that at least one of the selected two is right-handed is 0.9919
Let
[tex]p \to[/tex] left-handed people
[tex]q \to[/tex] right-handed people
So, we have:
[tex]p = 9\%[/tex]
The probability that at least one is right-handed is calculated as follows:
[tex]Pr =1 - P(None)[/tex] --- Complement rule
Where:
[tex]P(None) \to[/tex] The probability that none of the selected 2 is right-handed; in other words, the selected 2 are left-handed.
So, we have:
[tex]P(None) = p \times p[/tex]
[tex]P(None) = 9\% \times 9\%[/tex]
[tex]P(None) = 0.0081[/tex]
Substitute [tex]P(None) = 0.0081[/tex] in [tex]Pr =1 - P(None)[/tex]
[tex]Pr = 1 - 0.0081[/tex]
[tex]Pr = 0.9919[/tex]
Hence, the probability that at least one of the selected two is right-handed is 0.9919
Read more about probability at:
https://brainly.com/question/24297863
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