nairobbyg
Answered

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The graph below shows the total costy (in dollars) of owning and operating a compact car
where x is the number of miles driven.
Owning and Operating a Compact Car
S10,000
58000
(20,000, 7200)
56000
Total Cost in dollars)
S-1000
S2000
(5000, 1800)
25.000
3000 10,000 15.000 20,000
Miles Driven
Source: Federal Highway Administration
**This question consists of two answers, Please read carefully**
1) Based on the graph, what is the growth per year of owning and operating a compact car?
Select)
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2) If this trend continues, what would be the cost of owning and operating a compact car that

The Graph Below Shows The Total Costy In Dollars Of Owning And Operating A Compact Car Where X Is The Number Of Miles Driven Owning And Operating A Compact Car class=

Sagot :

MrRoyal

The relationship between the cost and the miles driven, as presented on the graph is an illustration of a linear equation or a linear graph.

  • The growth rate per year is $0.36 per year
  • The cost of owning and operating the car is $7201.44

A. The growth per year

This simply means that we calculate the slope (m) of the graph.

This is calculated using:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

From the graph, we have:

[tex](x_1,y_1) = (5000, 1800)[/tex]

[tex](x_2,y_2) = (20000, 7200)[/tex]

So, we have:

[tex]m = \frac{7200 - 1800}{20000 - 5000}[/tex]

[tex]m = \frac{5400}{15000}[/tex]

[tex]m = 0.36[/tex]

Hence, the growth per year is: $0.36 per year

B. The cost, when the number of miles is 20004 miles

The equation of a straight line is:

[tex]y = mx + b[/tex]

Where:

[tex]m = 0.36[/tex] --- the slope

[tex]b = 0[/tex] --- the point where the graph crosses the y-axis.

So, we have:

[tex]y = 0.36x + 0[/tex]

[tex]y = 0.36x[/tex]

The cost when the miles driven is 20004, is:

[tex]y = 0.36 \times 20004[/tex]

[tex]y = 7201.44[/tex]

The cost of owning and operating the car is $7201.44

Read more about linear graphs at:

https://brainly.com/question/11897796

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