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When a falling body is at distance above the surface which is 4 times the Earth radius what is the acceleration due to Earth gravitation

Sagot :

Answer:

Explanation:

g = GM/R²

as gravity decreases by the inverse of the square of the distance, increasing the distance by 4 times will reduce gravity to 1/16 that at the surface

9.8 / 16 = 0.61 m/s²

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