Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Following are the SQL query commands to the given question:
Query:
select customer_name /*using inner select query */
from
(
/* select column names*/
SELECT customer_name,
transaction_time,
next_transaction_time,
TIME_TO_SEC(TIMEDIFF(next_transaction_time, transaction_time)) as difference
FROM ( SELECT customer_name,
transaction_time,
( SELECT MIN(transaction_time)
FROM customer_transactions T2
WHERE T2.customer_name = T1.customer_name
AND T2.transaction_time > T1.transaction_time
) AS next_transaction_time
FROM customer_transactions T1
) AS T
) X
/*Using group by clause with min and max method*/
GROUP BY customer_name HAVING MIN(difference) = 10 and MAX(difference) = 10
Explanation of query:
- In this question, Subqueries, group by clause, with the max and min method is used which purpose can be defined as follows:
- It is utilized for returning information which is used to better limit the data to be found in the primary query.
- It returns no or more rows through one or more tables or views of the database.
- It organizes rows into groups depending on its values for one or more columns.
- Grouping is usually utilized to use some kind of aggregate function for every group.
- The function MIN() returns the lowest value of the column chosen.
- The function MAX() returns the highest number in the column chosen.
Learn more:
brainly.com/question/1765746
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.