Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Pls tell the answer fast please​

Pls Tell The Answer Fast Please class=

Sagot :

Let, ∠ZYQ = ∠QYP = a°

Since, XYP is a straight line,

⇒ ∠XYZ + ∠ZYP = 180° (Linear Pair)

⇒∠ZYP = 180°- ∠XYZ

⇒∠ZYP = 180° - 64°

⇒∠ZYP = 116°

As it's given, YQ is the bisector of ∠ZYP,

⇒∠ZYQ = ∠QYP = ½ ZYP

= ½ × 116°

= 58°

⇒∠XYQ = ∠XYZ + ∠ZYQ

= 64° + 58°

= 112°

[Escape (∠XYQ value) if ya want because in Question it's not mentioned to find the value of ∠XYQ but we need need to find the value of ∠ZYQ, in order to find the reflex of it]

Now, We've to also find the reflex of

∠ZYQ,

⇒ Reflex of ∠ZYQ = 360° - ∠ZYQ

= 360° - 58°

= 302°

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.