We have that the values for F north,
F east,
F up are
- [tex]F_N=1.09090909*10^{-5}[/tex]
- [tex]F_E=5.18181818*10^{-6}[/tex]
- [tex]F_E=2*10^{-6}[/tex]
From the Question we are told that
electric force [tex]F_1 = 1.2 x 10^{-3} N(N)[/tex]
electric force , [tex]F_2=5.7 x 10^{-4} N(E)[/tex]
electric force , [tex]F_3=2.2 x 10^{-4} N (U)[/tex]
charge on this ball one [tex]q_1= 110 nC.[/tex]
charge on this ball two [tex]q_2= -50 nC.[/tex]
Generally the equation for the F north is mathematically given as
[tex]F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}[/tex]
[tex]F_N=1.09090909*10^{-5}[/tex]
For F East
[tex]F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}[/tex]
[tex]F_E=5.18181818*10^{-6}[/tex]
For F UP
[tex]F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}[/tex]
[tex]F_E=2*10^{-6}[/tex]
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https://brainly.com/question/21811998
