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Find the surface area of a cylinder with a base radius of 2 cm and a height of 8 cm

Sagot :

manteadelaide510

Answer:

82.6cm2

Step-by-step explanation:

[tex]\pi {r}^{2} + \pi {r}^{2} + 2 \pi \: r h[/tex]

[tex]\pi = \frac{22}{7} [/tex]

radius =2cm

height=8cm

[tex]( \frac{22}{7} \times 2 \times 2 )+ ( \frac{22}{7} \times 2 \times 2) + (2 \times \frac{22}{7} \times 2 \times 8)[/tex]

Multiplying the numerators and The whole numbers, we have

[tex] \frac{88}{7} + \frac{88}{7} + \frac{402}{7} [/tex]

Since the denominators of the fractions are the same, we add the numerators.

[tex] \frac{88 + 88 + 402}{7} = \frac{578}{7} \\ which \: becomes \\ [/tex]

[tex] 82.57{cm}^{2} = 82.6 {cm}^{2} [/tex]

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