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3x^2(4x^3-2x^2+7x-4)

Sagot :

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>> Given Question :

3x²(4x³ - 2x² + 7x - 4)

>> Required Solution :

12x⁵ - 6x⁴ + 21x³ - 12x²

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Given :

[tex] \tt \: 3x^2(4x^3-2x^2+7x-4)[/tex]

Answer :

[tex] \tt \: 12 {x}^{5} - 6 {x}^{4} + 21 {x}^{3} - 12 {x}^{2} [/tex]

Explanation :

[tex]\tt \: 3x^2(4x^3-2x^2+7x-4) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \: \: \: \: = \tt(3 {x}^{2} \times 4 {x}^{3} ) + [3 {x}^{2} \times ( - 2 {x}^{2} )] + (3 {x}^{2} \times 7{x}^{} ) + [3 {x}^{2} \times ( - 4 {}^{} )] \\ \\ \\ = \tt \: 12 {x}^{5} - 6 {x}^{4} + 21 {x}^{3} - 12 {x}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Hope it helps you!! :)