jsichalwe1990
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

FIND THE CENTRE OF GRAVITY OF AN INVERTED T-SECTION WITH FLANGE 60 mm x 10mm and WEB 50mm x 10mm​

Sagot :

Answer:

Explanation:

Assuming the material of the T-section is uniform, the weight of each portion will be proportional to the area and the CG of each portion will be at its geometric center.

From symmetry, the CG will be along the midline of the web

Area of flange 60(10) = 600 mm²

Area of web 50(10) = 500 mm²

let y be the position of the assembly CG.

Let the flange bottom be coincident on the x axis.

y(600 + 500) = 600(10/2) + 500(10 + 50/2)

1100y = 3000 + 17,500

y = 18.63636363...

y ≈ 18.6 mm

View image Аноним
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.