jsichalwe1990
Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

FIND THE CENTRE OF GRAVITY OF AN INVERTED T-SECTION WITH FLANGE 60 mm x 10mm and WEB 50mm x 10mm​

Sagot :

Answer:

Explanation:

Assuming the material of the T-section is uniform, the weight of each portion will be proportional to the area and the CG of each portion will be at its geometric center.

From symmetry, the CG will be along the midline of the web

Area of flange 60(10) = 600 mm²

Area of web 50(10) = 500 mm²

let y be the position of the assembly CG.

Let the flange bottom be coincident on the x axis.

y(600 + 500) = 600(10/2) + 500(10 + 50/2)

1100y = 3000 + 17,500

y = 18.63636363...

y ≈ 18.6 mm

View image Аноним
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.