Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A robot used in a pharmacy picks up a medicine bottle at t=0. It accelerates at 0.15 m/s2 for 7.0 s , then travels without acceleration for 64 s and finally decelerates at -0.50 m/s2 for 2.1 s to reach the counter where the pharmacist will take the medicine from the robot. From how far away did the robot fetch the medicine?

Sagot :

Answer:

Explanation:

distance while accelerating

d = ½at² = ½(0.15)7.0² = 3.675 m

velocity at the end of 7 s

v = at = 0.15(7.0) = 1.05 m/s

distance at constant velocity

d = vt = 1.05(64) = 67.2 m

distance while decelerating

d = ut + ½at² = 1.05(2.1) + ½(-0.50)2.1² = 1.1025 m

velocity at the end of deceleration

v = u + at = 1.05 + (-0.5)2.1 = 0 m/s

total distance traveled

d = 3.675 + 67.2 + 1.1025 = 71.9775 m

rounding to the two significant figures of the question numerals

d = 72 m

that's a HUGE pharmacy.

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.