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Sagot :
Answer:
Explanation:
distance while accelerating
d = Β½atΒ² = Β½(0.15)7.0Β² = 3.675 m
velocity at the end of 7 s
v = at = 0.15(7.0) = 1.05 m/s
distance at constant velocity
d = vt = 1.05(64) = 67.2 m
distance while decelerating
d = ut + Β½atΒ² = 1.05(2.1) + Β½(-0.50)2.1Β² = 1.1025 m
velocity at the end of deceleration
v = u + at = 1.05 + (-0.5)2.1 = 0 m/s
total distance traveled
d = 3.675 + 67.2 + 1.1025 = 71.9775 m
rounding to the two significant figures of the question numerals
d = 72 m
that's a HUGE pharmacy.
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