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Sagot :
The maximum friction force provides the most significant deceleration (of magnitude a)
(With F
n
=mg in this case).
Using Newton’s second law, we find
a=f
s, max
/m=μ
s
g
In this calculation, it is vital first to convert v = 48km/hr to 13m/s.
This gives the shortest distance to stop:△x = v
2
/2a=36m.
(With F
n
=mg in this case).
Using Newton’s second law, we find
a=f
s, max
/m=μ
s
g
In this calculation, it is vital first to convert v = 48km/hr to 13m/s.
This gives the shortest distance to stop:△x = v
2
/2a=36m.
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