jongun6k
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Thomas threw a ball down a pit that was 400m deep. a) How long did it take to land? b) What speed was it going when it landed?​

Sagot :

leena

Hi there!

a)

We can use the equation t = √2d/g to solve. (Let's let g = 10 m/s²)

**How to get this equation**

We have the equation:

Δd = vit + 1/2at²

For freefall, we know that vi = 0, so we are left with:

Δd = 1/2at²

We know that a = g. Rearrange in terms of t:

2Δd / a = t²

Square root both sides:

√(2d/a) = t

Plug in the height and gravity:

t = √2(400)/10 = √800/10 = √80 ≈ 8.94 sec

b)

Find the final speed using the following formula:

vf = √2gd

**How to derive**

We know the equation:

vf² = vi² + 2ad

vi = 0, so:

vf² = 2ad

Square root both sides:

vf = √2ad

vf = √2(400)(10) = √8000 ≈ 89.44 m/s

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.