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If two lines y = x and y = x - 4 are tangent to a circle at ( 2, 2 ) and ( 4,0 ) respectively, then what is the equation of the circle?​

Sagot :

Answer:

i don't known

Step-by-step explanation:

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The equation of the circle with the given parameters is (x-3)² + (y-1)² = 2.

We need to find the equation of the circle.

What is the circle equation?

We know that the general equation for a circle is ( x - h )² + ( y - k )²= r², where ( h, k ) is the centre and r is the radius.

Let centre O be (a,b).

(a-2)² + (b-2)² = (a-4)² +b² , Or, a-b = 2

Means centre is (b+2, b)

Distance of centre from x-y=0 is 2/√2 = √2 =radius

Distance between centre and (4,0) = Also radius

(b-2)² +b² = 2 or, b² -2b +1= 0 or b = 1,

So centre is (3,1) and the equation of the circle is (x-3)² + (y-1)² = 2.

Therefore, the equation of the circle is (x-3)² + (y-1)² = 2.

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