Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
We have that perpendicular distance and the two resulting couples
[tex]m=-16.39m\\\\m=16.39Nm(cw)[/tex]
From the question we are told that
Two parallel 60-N forces
A and C of a 200-mm square plate.
Generally the equation for AC is mathematically given as
[tex]AC=\sqrt{0.2^2+(0.2^2)}\\\\AC=0.2\sqrt{2m}\\\\sin75=\frac{d}{AC}\\\\d=(0.2\sqrt{2})sin75\\\\d=0.2732m\\\\m=Fxd\\\\m=-60x0.2732m\\\\m=-16.39m[/tex]
b)
[tex]mFm=Fm*0.2\\\\mFm=-30V_3x0.2\\\\mF_m=-6v_3\\\\mF_v=-6Nm\\\\Thereforem=16.39Nm(cw)[/tex]
For more information on this visit
https://brainly.com/question/23366835?referrer=searchResults
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.