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A 9 -slug mass hangs by a rope from the ceiling. Using the standard value of gravitational acceleration g = 32.2 fts 2, what is the tension in the rope?



Sagot :

spectrojamz

Answer:

For the Mass to hang without falling

It simply means that the Tension that supports the weight force has to be Equal to or greater than it.

T=W

T= mg

m= 9 slugs

g=32.2ft/s².

T= 9 x 32.2

T= 289.8 slug.ft/s².

Or in normal units

1 Slug = 14.59Kg

1ft = 0.3048m

m= 9 slugs = 131.345kg

g =32.2ft/s² = 9.8m/s²

T= 9.8 x 131.345

T= 1,287.18N.

Cricetus

The tension in the rope will be "300 lbf".

According to the question,

  • Mass, m = 9
  • Gravitational acceleration, g = 32.2

Now,

→ The tension in the rope will be:

= [tex]Mass\times Gravitational \ acceleration[/tex]

or,

= [tex]m\times g[/tex]

By substituting the values, we get

= [tex]9\times 32.2[/tex]

= [tex]298.8 \ lbf[/tex]

or,

= [tex]300 \ lbf[/tex]

Thus the above is the correct solution.

Learn more about tension here:

https://brainly.com/question/6365940

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