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A hiker leaves camp and walks 5 km on a
bearing of 058º. He stops for a break, then
continues walking for another 8 km on
a bearing of 103°. He stops again before
heading straight back. Find the distance
back to camp from the second stop.


Sagot :

The distance can be determined by applying the cosine rule. Thus the distance back to camp from the second stop is 5.7 km

The appropriate method to determine the distance is by the application of Cosine rule. Let the distance be represented by x.

Thus;

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] - 2ab Cos C

C = [tex]058^{o}[/tex] + [tex]77^{o}[/tex]

   = [tex]135^{o}[/tex]

So that,

[tex]x^{2}[/tex] = [tex]5^{2}[/tex] + [tex]8^{2}[/tex] - 2(5 x 8) Cos [tex]135^{o}[/tex]

   = 25 + 64 - 80 (-0.7071)

   = 89 - 56.57

[tex]x^{2}[/tex] = 32.43

x = [tex]\sqrt{32.43}[/tex]

 = 5.7

x = 5.7 km

Therefore, the distance back to camp from the second stop is 5.7 km.

A sketch for the question is attached to this answer for clear understanding.

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