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help.? geometry basics homework 2: segment addition postulate

Help Geometry Basics Homework 2 Segment Addition Postulate class=

Sagot :

abidemiokin

The value of x is 3 given that ST = 8x + 11 and TU = 12x-1

The point that bisects a line divides the line into two equal parts

If T is the midpoint of SU, the following are true:

  • ST = TU
  • ST + TU = SU

Given the following

ST = 8x + 11

TU = 12x-1

Since ST = TU

8x+11 = 12x-1

8x - 12x = -1 - 11

-4x = -12

x = 12/4

x = 3

Hence the value of x is 3 given that ST = 8x + 11 and TU = 12x-1

Learn more here: https://brainly.com/question/17204733

Answer:

QS = 34

Step-by-step explanation:

Question: 12

1. 5x - 3 = 21 - x

2. 6x = 24

3. x = 4

so; 5(4)-3 = 17 and 21-4=17

Which means 17+17 = QS

QS=34

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