Answer:
1.5 × [tex]10^2[/tex] J
Explanation:
The initial force, which in this case is the external force is equal to 15N. Logically, when 150 Joules of work is done upon that system the overall energy will increase by that very same amount of work applied on the system which is 150 J.
The total energy of that system increases by 150 Joule. The correct answer is option (1)
Given that 150 joules of work is done on a system by an external force of 15 newtons in 20 seconds
The impulse on the system = the momentum of the system
That is,
Ft = mV
15 x 20 = mV
mV = 300 Ns
Since work done = energy
W = 1/2mV x V
150 = 0.5 x 300V
V = 1 m/s
With this, we can calculate the acceleration and the distance travelled.
Using equation one of motion,
V = u + at
1 = 0 + 20a
a = 1/20
a = 0.05 m/[tex]s^{2}[/tex]
Using equation three of linear motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS
Substituting all parameters into the equation
[tex]1^{2}[/tex] = 0 + 2 x 0.05 S
S = 1/0.1
S = 10 m
The work done = Force x distance
The work done = 15 x 10
The work done = 150 Joule.
Therefore, the total energy of that system increases by 150 Joule.
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