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When 150 joules of work is done on a system by an external force of 15 newtons in 20. seconds, the total energy of that system increases by.

(1) 1.5 × 102 J
(2) 2.0 × 102 J
(3) 3.0 × 102 J
(4) 2.3 × 103 J

Please include an explanation

Sagot :

Zezima

Answer:

1.5 × [tex]10^2[/tex] J

Explanation:

The initial force, which in this case is the external force is equal to 15N. Logically, when 150 Joules of work is done upon that system the overall energy will increase by that very same amount of work applied on the system which is 150 J.

temdan2001

The total energy of that system increases by 150 Joule. The correct answer is option (1)

Given that 150 joules of work is done on a system by an external force of 15 newtons in 20 seconds

The impulse on the system = the momentum of the system

That is,

Ft = mV

15 x 20 = mV

mV = 300 Ns

Since work done = energy

W = 1/2mV x V

150 = 0.5 x 300V

V = 1 m/s

With this, we can calculate the acceleration and the distance travelled.

Using equation one of motion,

V = u + at

1 = 0 + 20a

a = 1/20

a = 0.05 m/[tex]s^{2}[/tex]

Using equation three of linear motion.

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS

Substituting all parameters into the equation

[tex]1^{2}[/tex] = 0 + 2 x 0.05 S

S = 1/0.1

S = 10 m

The work done = Force x distance

The work done = 15 x 10

The work done = 150 Joule.

Therefore,  the total energy of that system increases by 150 Joule.

Learn more about work done here: https://brainly.com/question/8119756

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