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Sagot :
We have that the work function of the metal
[tex]\phi=1.227*10^{-18}J[/tex]
From the Question we are told that
UV radiation (λ = 162 nm)
Kinetic energy [tex]K.E =3.54*10-19 J.[/tex]
Generally the equation for Kinetic energy is mathematically given as
[tex]KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}[/tex]
[tex]\phi=1.227*10^{-18}J[/tex]
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