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A physician has ordered 325 mg of atropine, intramuscularly. If atropine were available as 0.50 g/mL of solution, how many milliliters would you need to give?

Sagot :

pstnonsonjoku

You would need to give 0.65 mL.

Since the solution concentration is given in g/mL

We have to convert the mass of atropine to g

1000 mg make 1 g

325 mg = 325/1000 * 1 = 0.325 g

Now;

0.50 g is contained in 1 mL

0.325 g should be contained in 0.325 g * 1 mL/0.50 g

= 0.65 mL

Learn more: https://brainly.com/question/4736731

ajeigbeibraheem

Provided that a physician has ordered 325 mg of atropine, intramuscularly and the atropine was available as 0.50 g/mL of solution, the volume of atropine needed to be given in millimeters is 0.65 mL.

From the given information:

The mass of the drug (atropine) ordered for = 325 mg

The density of the available solution of atropine = 0.50 g/mL

The objective is to determine the volume of the atropine that will be given by the physician.

Using the relation for  [tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]

[tex]\mathbf{0.50 \ g/mL= \dfrac{325 \ mg}{volume}}[/tex]

[tex]\mathbf{volume= \dfrac{325 \ mg}{0.50 \ g/mL}}[/tex]

Now, the next step is to make the unit to be similar.

Since the volume is to be determined in milliliters;

We know that:

1 mg = 0.001 grams

∴

325 mg to grams will be = (325× 0.001 grams)

= 0.325 grams

Now;

[tex]\mathbf{volume= \dfrac{0.325 \ g}{0.50 \ g/mL}}[/tex]

[tex]\mathbf{volume= 0.65 \ mL}[/tex]

In conclusion, the volume that will be needed by the physician is 0.65 mL.

Learn more about atropine here:

https://brainly.com/question/17005997?referrer=searchResults

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