Answer:
[tex]\boxed {\boxed {\sf y=8x-14}}[/tex]
Step-by-step explanation:
We are asked to find the equation of a line in slope-intercept form. We are given a point and a slope, so we can use the point-slope formula.
[tex]y-y_1= m(x-x_1)[/tex]
In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of the line is 8 and it passes through the point (1, -6). Therefore,
Substitute these values into the formula.
[tex]y- (-6) = 8(x-1)[/tex]
Remember that 2 back to back subtraction signs are the same as an addition sign.
[tex]y+6=8(x-1)[/tex]
The line must be in slope-intercept form or y=mx+b (m is the slope and b is the y-intercept. We must isolate the variable y on one side of the equation. First, distribute on the right side of the equation. Multiply each term inside the parentheses by 8.
[tex]y+6 = (8*x) + (8*-1)[/tex]
[tex]y+6= (8x)+ (-8)[/tex]
[tex]y+6=8x-8[/tex]
6 is being added to y. The inverse operation of addition is subtraction, so we subtract 6 from both sides of the equation.
[tex]y+6-6=8x-8-6[/tex]
[tex]y=8x-8-6[/tex]
[tex]y= 8x-14[/tex]
The equation of the line in slope-intercept form is y=8x-14. The slope is 8 and the y-intercept is -14.
Answer:
y=8x-14
Step-by-step explanation:
Hi there!
We want to write the equation of the line that passes through (1, -6) and has a slope of 8 in slope-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
As we are already given the slope (8), we can immediately plug that into the equation
So far, the equation of the line is:
y=8x+b
Now we need to find b
The line passes through the point (1, -6), which means that the point is a solution to the equation; when plugged into the equation, it'll create a true statement. This can help us find unknown variables, like b
Substitute 1 as x and -6 as y in the equation to solve for b
-6=8(1)+b
Multiply
-6=8+b
Subtract 8 from both sides
-14=b
Substitute -14 as b into the equation
y=8x-14
Hope this helps!
