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find the distance between the point.(5,5) amd the line -3x-4y+10=0

Sagot :

ferrybukantoro

Answer:

5

Step-by-step explanation:

the formula of the distance between

the point (p, q) and the line ax + by +c = 0 =>

d = |p.a + q.b +c| / √(a²+b²)

d = |5(-3)+5(-4)+10| / √[(-3)²+(-4)²]

= |(-15-20+10)|/√25

= |-25|/ 5

= 25/5

= 5

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