Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Please help me out if you can!


Please Help Me Out If You Can class=

Sagot :

Step-by-step explanation:

f(4) means x = 4.

what function definition can we use ? the second one for x >= 4

so,

4² - 10×4 + 21 = 16 - 40 + 21 = -3

f(4) = -3

f(0) means x = 0.

so, we use the first function definition (x < 4).

0 - 4 = -4

f(0) = -4

f(x) = 0

for the first function definition this would only be possible for x = 4. but again, for x = 4 this is invalid.

so, we can only look at the second function definition.

x² - 10x + 21 = 0

a squared equation is solved by

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -10

c = 21

x = (10 ± sqrt(100 - 84))/2 = (10 ± sqrt(16))/2 =

= (10 ± 4)/2 = 5 ± 2

x1 = 5 + 2 = 7

x2 = 5 - 2 = 3, which contradicts again the validity of the second function definition (x >=4).

so, the only valid solution is x = 7