Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

16.(2-3x)+x^2.(3x-2)=0

Sagot :

Tasyha

Answer:

[tex] x_{1} = - 1 \: . \: \: x_{2} = \frac{2}{3} . \: \: x_{3} = 1 [/tex]

Step-by-step explanation:

[tex](2 - 3x) + {x}^{2} (3x - 2) = 0 \\ 2 - 3x + {x}^{3} - 2 {x}^{2} = 0 \\ - (3x - 2) + {x}^{2} (3x - 2) = 0 \\ - (3x - 2)(1 - {x}^{2} ) = 0 \\ (3x - 2)(1 - {x}^{2} ) = 0 \\ 3x - 2 = 0 \\ 1 - {x}^{2} = 0 \\ x = \frac{3}{2} \\ x = - 1 \\ x = 1 \\ [/tex]

[tex]\boxed{\green{ x_{1} = - 1 \: . \: \: x_{2} = \frac{2}{3} . \: \: x_{3} = 1}}[/tex]

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.