Answer:
recall your d = rt, distance = rate * time.
let's say by the time the car gets in the highway, the truck has already been running for 5 minutes, and say by the time they meet the truck has been running for "t" hours, so the car has then been runnning for 5 minutes less than "t", now, since "t" is hours well, 5 minutes is just 5/60 or 1/12 of "t", so the car has been running when they meet for "t - 1/2"
now, just before the car passes the truck, they first have to meet, at that point, the distance travelled by both is exactly the same, say "d" miles.
which is about 26 minutes and 25 seconds.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the time the car is travelling is t.
The truck is travelling 5 min or 1/12 hr more.
The distance travelled by both is same at the time the car catches the truck, d.
Now we have:
Eliminate d and solve for t:
