[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
- [tex] \sf2 \left( 4- \frac{ 1 }{ 3 } u \right) = -u+2[/tex]
[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
[tex] \sf \: 2 \left( 4- \frac{ 1 }{ 3 } u \right) = -u+2[/tex]
Use the distributive property to multiply 2 by [tex]\sf 4-\frac{1}{3}u[/tex].
[tex] \sf \: 8+2\left(-\frac{1}{3}\right)u=-u+2 [/tex]
Express [tex]\sf2\left(-\frac{1}{3}\right)[/tex] as a single fraction.
[tex] \sf \: 8+\frac{2\left(-1\right)}{3}u=-u+2 [/tex]
Multiply 2 and -1 to get -2.
[tex] \sf \: 8+\frac{-2}{3}u=-u+2 [/tex]
Add u to both sides.
[tex] \sf \: 8-\frac{2}{3}u+u=2 [/tex]
Combine [tex]\sf-\frac{2}{3}u[/tex] and u to get [tex]\sf\frac{1}{3}u[/tex].
[tex] \sf \: 8+\frac{1}{3}u=2 [/tex]
Subtract 8 from both sides.
[tex] \sf\frac{1}{3}u=2-8 [/tex]
Subtract 8 from 2 to get -6.
[tex] \sf\frac{1}{3}u=-6 [/tex]
Multiply both sides by 3, which is the reciprocal of 1/3.
[tex] \sf \: u=-6\times 3 [/tex]
Multiply -6 and 3 to get -18.
[tex] \boxed{ \boxed{\bf \: u=-18 }}[/tex]
