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Consider a two-link network where Host A is connected to the router by a 1 Mbps link with 10 ms propagation delay and the router is connected to Host B by a 15 Mbps link with a 25 ms propagation delay. Host A sends a 1500-byte packet to Host B. What is the end-to-end delay (in ms) for the packet between Host A and Host B?

Sagot :

The delay in transmission depends on the amount of data transmitted and the transmission rate.

Packet size to be sent [tex]\bold{= 1500\ bytes}[/tex]

                                        [tex]\bold{= 1500 \times 8 \ bits}\\\\\bold{= 12000\ bits}[/tex]

[tex]\to \bold{\text{Delay in transmission} = \frac{\text{number of bits}}{\text{rate of transmission}}}[/tex]

Take into account bits [tex]\bold{= 12,000 \ bits}[/tex]

Rate of transmission [tex]\bold{ = 15\ Mbps = 15000000\ bps}[/tex]

Calculate the time between transmission A and router:  

[tex]\to \bold{\text{Delay in transmission} = \frac{\text{number of bits}}{\text{rate of transmission}}}[/tex]

                                       [tex]\bold{= \frac{12000}{1000000}}\\\\\bold{= \frac{12}{1000}\ seconds }\\\\ \bold{= 12\ ms}[/tex]

Compute the time between router B:

[tex]\to \bold{\text{Delay in transmission} = \frac{\text{number of bits}}{\text{rate of transmission}}}[/tex]

                                       [tex]\bold{= \frac{12000}{15000000}} \\\\\bold{= \frac{12}{15000}} \\\\\bold{= 0.8\ ms}\\\\[/tex]

The total end-to-end delay is due to a delay in propagation and a delay in transfer.

The formula to calculate total delay:

[tex]\text{Total delay} = \text{Propagation delay of Host A} + \text{transmission delay between A and router} + \text{Propagation delay of router} +\text{ tranmission delay between router and B}[/tex]

[tex]\bold{= 10 + 12 + 25 + 0.8}\\\\\bold{= 47.8 \ ms}[/tex]

So, the total delay is "47.8 ms".

Learn more:

brainly.com/question/24431127

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