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Write the equation of the line that passes through point (-2,-6) with slope 2/3 in point-slope form and in slope-intercept form

Sagot :

Answer:

y=2/3x-14/3

Step-by-step explanation:

y-y1=m(x-x1)

y-(-6)=2/3(x-(-2))

y+6=2/3(x+2)

y=2/3x+4/3-6

y=2/3x+4/3-18/3

y=2/3x-14/3